10 REM LM565DES.BAS 15 CLS : PI=3.14159 20 PRINT" A PROGRAM TO DESIGN A PHASE LOCK LOOP USING THE LM565 IC" 30 PRINT" WRITTEN BY RUSS KINCAID, 18 JUNE 1999" : PRINT 40 PRINT"THIS IS A TYPE 1 SERVO, IT HAS PHASE ERROR THAT INCREASES" 50 PRINT"AS THE FREQUENCY DEVIATES FROM CENTER" : PRINT 60 PRINT"THE DEMODULATOR OUTPUT IS 3.6K OHMS, SO IT NEEDS TO BE BUFFERED" 70 PRINT 80 INPUT"WHAT IS THE TOTAL SUPPLY VOLTAGE ";VC 90 INPUT"WHAT IS THE CENTER FREQUENCY IN HZ (300KHZ/MIL 250KHZ/COM MAX) ";FO 100 PRINT:PRINT"THE MAX HOLD IN RANGE IS: ";8*FO/VC;" HZ" 105 KOKD = 33.6*FO/VC 107 R1=3600 110 PRINT:REM FO=0.3/RO/CO 112 PRINT"CHOOSE THE OSCILLATOR RESISTOR (RO) TO BE BETWEEN 2K & 20K "; 114 INPUT RO 116 CO=.3/RO/FO : PRINT "OSCILLATOR CAP. (CO) = ";CO 118 INPUT"TRY ANOTHER VALUE FOR RO Y OR N ";Y$ 119 IF LEFT$(Y$,1)="y" OR LEFT$(Y$,1)="Y" THEN 112 120 INPUT"WHAT IS THE CLOSED LOOP BANDWIDTH TO BE DESIGNED (HZ) ";BW 130 PRINT "YOU MAY SPECIFY THE DAMPING FACTOR, 0.5 WILL GIVE SOME OVERSHOOT," 140 PRINT"1.0 IS OPTIMUM AND MORE THAN 1 WILL SLOW THE RESPONSE" 150 INPUT"WHAT VALUE ";ZETA 160 REM THE OPEN LOOP GAIN IS: K=33.6*FO/VC 170 K=33.6*FO/VC 180 C1=(1/R1)*(KOKD/4/PI^2/BW^2-ZETA/PI/BW) 190 REM T2=R2*C1 = ZETA/PI/BW AND T3=R1*C2